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Calculus for Team-Based Inquiry Learning: 2024 Early Edition

TBIL Institute Fellows

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Section 3.2 Linear approximation (AD2)

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Subsection 3.2.1 Activities

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Definition 3.2.1.

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The linear approximation (or tangent line approximation or linearization) of a function f(x) at x=a is the tangent line L(x) at x=a. In formulas, L(x) is the linear function
L(x)=f′(a)(x−a)+f(a).
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Notice that this is obtained by writing the tangent line to f(x) at (a,f(a)) in point-slope form and calling the resulting linear function L(x). The linear approximation L(x) is a linear function that looks like f(x) when we zoom in near x=a.
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Activity 3.2.2.

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Without using a calculator, we will use calculus to approximate ln⁡(1.1).
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(a)
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Find the equation of the tangent line to ln⁡(x) at x=1. This will be your linear approximation L(x). What do you get for L(x)?
  1. L(x)=x
  2. L(x)=x+1
  3. L(x)=x−1
  4. L(x)=−x+1
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(b)
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As 1.1 is close to 1, we can use L(1.1) to approximate ln⁡(1.1). What approximation do you get?
  1. ln⁡(1.1)≈1.1
  2. ln⁡(1.1)≈2.1
  3. ln⁡(1.1)≈0.1
  4. ln⁡(1.1)≈−0.1
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(c)
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Sketch the tangent line L(x) on the same plane as the graph of ln⁡(x). What do you notice?
Figure 60. The graph of ln⁡(x)
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Activity 3.2.3.

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Using the equation of the tangent line to the graph of ln⁡(x) at x=1 and the shape of this graph, you can show that for all values of x, we have that ln⁡(x)≤x−1.
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(a)
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Compute the second derivative of ln⁡(x). What do you notice about the sign of the second derivative of ln⁡(x)? What does this tell you about the shape of the graph?
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(b)
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Conclude that because the graph of ln⁡(x) has a certain shape, the graph will bend below the tangent line and so that ln⁡(x) will always be smaller than the tangent line approximation L(x)=x−1.
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Activity 3.2.4.

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In this activity you will approximate power functions near x=1.
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(a)
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Find the tangent line approximation to x2 at x=1.
  1. L(x)=2x
  2. L(x)=2x+1
  3. L(x)=2x−1
  4. L(x)=−2x+1
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(b)
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Show that for any constant k, the tangent line approximation to xk at x=1 is L(x)=k(x−1)+1.
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(c)
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Someone claims that the square root of 1.1 is about 1.05. Use the linear approximation to check this estimate. Do you think this estimate is about right? Why or why not?
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(d)
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Is the actual value 1.1 above or below 1.05? What feature of the graph of x makes this an over or under estimate?
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Remark 3.2.5.

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If a function f(x) is concave up around x=a, then the function is turning upwards from its tangent line. So when we use a linear approximation, the value of the approximation will be below the actual value of the function and the approximation is an underestimate. If a function f(x) is concave down around x=a, then the function is turning downwards from its tangent line. So when we use a linear approximation, the value of the approximation will be above the actual value of the function and the approximation is an overestimate.
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Activity 3.2.6.

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Suppose f has a continuous positive second derivative and Δx is a small increment in x (like h in the limit definition of the derivative). Which one is larger...
f(1+Δx)orf′(1)Δx+f(1)?
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Activity 3.2.7.

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A certain function p(x) satisfies p(7)=49 and p′(7)=8.
  1. Explain how to find the local linearization L(x) of p(x) at 7.
  2. Explain how to estimate the value of p(6.951).
  3. Suppose that p′(7)=0 and you know that p″(x)<0 for x<7. Explain how to determine if your estimate of p(6.951) is too large or too small.
  4. Suppose that p″(x)>0 for x>7. Use this fact and the additional information above to sketch an accurate graph of y=p(x) near x=7.
Answer.
  1. L(x)=8x−7
  2. p(6.951)≈48.6064
  3. The estimate is too large.
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Activity 3.2.8.

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Let’s find the quadratic polynomial
q(x)=ax2+bx+c
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where a,b,c are parameters to be determined so that q(x) best approximates the graph of f(x)=ln⁡(x) at x=1.
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(a)
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We want to choose a,b,c such that our quadratic polynomial resembles f(x) at x=1. First thing, we want f(1)=q(1). What equation in a,b,c does this condition give you?
  1. a+b+c=1
  2. a+b+c=0
  3. c=0
  4. c=1
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(b)
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We also want f′(1)=q′(1). What equation in a,b,c does this condition give you?
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(c)
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Finally, we want f″(1)=q″(1). What equation in a,b,c does this condition give you?
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(d)
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Find a solution to this system of linear equations! Your answer will give you values of a,b,c that can be used to draw a quadratic approximating the natural logarithm. You can check your answer on Desmos https://www.desmos.com/calculator/bad2xrwmvl
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Observation 3.2.9.

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A linear approximation L(x) to f(x) at x=a is a linear function with
L(a)=f(a),L′(a)=f′(a).
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A quadratic approximation Q(x) to f(x) at x=a is a quadratic function with
Q(a)=f(a),Q′(a)=f′(a),Q″(a)=f″(a).
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Activity 3.2.10.

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Find the linear approximation L(x) of cos⁡(x) at x=0. Then find the quadratic approximation Q(x) of cos⁡(x) at x=0. Graph both and compare the two approximations!
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Activity 3.2.11.

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Suppose the function p(x) satisfies p(−2)=5, p′(−2)=1, and p″(x)<0 for x values nearby −2.
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(a)
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Explain and demonstrate how to find the linearization L(x) of p(x) at x=−2.
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(b)
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Explain and demonstrate how to estimate the value of p(−2.03) using this linearization.
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(c)
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Explain why your estimate of p(−2.03) is greater than or less than the actual value.
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(d)
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Sketch a possible graph of p(x) and its linearization L(x) nearby x=−2 to illustrate your findings.
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Subsection 3.2.2 Videos

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Figure 61. Video for AD2
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