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Section 8.3 Partial Sum Sequence (SQ3)

Activity 8.3.1.

Consider the sequence {an}n=0∞={12n}n=0∞.

(a)

Find the first 5 terms of this sequence.

(b)

Compute the following:

  1. a0.

  2. a0+a1.

  3. a0+a1+a2.

  4. a0+a1+a2+a3.

  5. a0+a1+a2+a3+a4.

Activity 8.3.2.

Consider the sequence {an}n=1∞={1n}n=1∞.

(a)

Find the first 5 terms of this sequence.

(b)

Compute the following:

  1. a1.

  2. a1+a2.

  3. a1+a2+a3.

  4. a1+a2+a3+a4.

  5. a1+a2+a3+a4+a5.

Definition 8.3.3.

Given a sequence {an}n=0∞ define the kth partial sum of {an} to be

Ak=∑i=0kai=a1+a2+⋯+ak.

Note that {An}=A0,A1,A2,… is itself a sequence called the partial sum sequence.

Activity 8.3.4.

Let an=23n. Find the following partial sums:

  1. A0.

  2. A1.

  3. A2.

  4. A3.

  5. A100.

Activity 8.3.5.

Consider the sequence an=23n. What is the best way to find the 100th partial sum A100?

  1. Sum the first 101 terms of the sequence {an}.

  2. Find a closed form for the partial sum sequence {An}.

Activity 8.3.6.

Expand the following polynomial products, and then reduce to as few summands as possible.

  1. (1−x)(1+x+x2).

  2. (1−x)(1+x+x2+x3).

  3. (1−x)(1+x+x2+x3+x4).

  4. (1−x)(1+x+x2+⋯+xn), where n is any nonnegative integer.

Activity 8.3.7.

Suppose S5=1+12+14+18+116+132. Without actually computing this sum, which of the following is equal to (1−12)S5?

  1. 12+14+18+116+132−164.

  2. 1−164.

  3. 1−12−14−18−116−132.

Activity 8.3.8.

Recall from Activity 8.3.4 that A100=2+23+232+233+234+⋯+23100=2(1+13+132+133+134+⋯+13100).

(a)

Which of the following is equal to (1−13)A100?

  1. 1−13101.

  2. 1−13100.

  3. 2(1−13101).

  4. 2(1−13100).

(b)

Based on your previous choice, write out an expression for A100.

Activity 8.3.9.

Suppose that {bn}n=0∞={(−2)n}n=0∞={1,−2,4,−8,…}. Let Bn=∑i=0nbi be the nth partial sum of {bn}.

(a)

Find simple expressions for the following:

  1. (1−(−2))B10.

  2. (1−(−2))B30.

  3. (1−(−2))Bn. Choose from the following:

    1. 1+(−2)n.

    2. 1−(−2)n.

    3. 1+(−2)n+1.

    4. 1−(−2)n+1.

    5. 1−2n.

(b)

Based on your previous answers, solve for the following:

  1. B10.

  2. B30.

  3. Bn. Choose from the following:

    1. 1−(−2)n+11−(−2)

    2. 1−(−2)n+11−2

    3. 1−(−2)n+11+(−2)

    4. 1−(−2)n1−2

    5. 1−(−2)n1−(−2)

Activity 8.3.10.

Consider the following sequences:

  1. {an}n=0∞={(−23)n}n=0∞.

  2. {bn}n=0∞={2⋅(−1)n}n=0∞.

  3. {cn}n=0∞={−3⋅(1.2)n}n=0∞.

(a)

Find the closed form for the nth partial sum for the geometric sequence An=∑i=0nai=∑i=0n(−23)n.

  1. 35(1−(−23)n+1).

  2. 53(1−(−23)n+1).

  3. 53(1+23(23)n).

  4. 35(1+23(23)n).

  5. 1−(−23)n+1.

(b)

Find the closed form for the nth partial sum for the geometric sequence Bn=∑i=0nbi=∑i=0n2⋅(−1)n.

  1. 2n+1.

  2. 1−(−1)n+1.

  3. 1+(−1)n.

  4. 2(1+(−1)n).

  5. 2(1−(−1)n+1).

(c)

Find the closed form for the nth partial sum for the geometric sequence Cn=∑i=0nci=∑i=0n−3⋅(1.2)n.

Activity 8.3.11.

Given the closed forms you found in Activity 8.3.10, which of the following limits are defined? If defined, what is the limit?

  1. limn→∞An.

  2. limn→∞Bn.

  3. limn→∞Cn.

Definition 8.3.12.

Given a sequence an, we define the limit of the series

∑n=k∞an:=limn→∞An

where An=∑i=knai. We call ∑n=k∞an an infinite series.

Activity 8.3.13.

Which of the following series are infinite?

  1. ∑n=0∞3(0.8)n.

  2. ∑n=0∞2(54)n.

  3. ∑n=0∞(56)n.

  4. ∑n=0∞12(81)n.

  5. ∑n=0∞10(−15)n.

Activity 8.3.14.

Let {an}n=1∞={1n−1n+1}=1−12,12−13,13−14,…. Let An=∑i=1nai=∑i=1n(1i−1i+1).

Which of the following is the best strategy for evaluating A4=(1−12)+(12−13)+(13−14)+(14−15)?

  1. Compute A4=(1−12)+(12−13)+(13−14)+(14−15)=12+16+112+120, then evaluate the sum.

  2. Rewrite A4=(1−12)+(12−13)+(13−14)+(14−15)=1+(−12+12)+(−13+13)+(−14+14)−15, then simplify.

Activity 8.3.15.

Recall from Activity 8.3.14 that {an}n=1∞={1n−1n+1} and An=∑i=1nai=∑i=1n(1i−1i+1).

Compute the following partial sums:

  1. A3.

  2. A10.

  3. A100.

Activity 8.3.16.

Recall from Activity 8.3.14 that {an}n=1∞={1n−1n+1} and An=∑i=1nai=∑i=1n(1i−1i+1).

Which of the following is equal to An?

  1. n−1n+1.

  2. 1−1n.

  3. 1−1n+1.

  4. 1−1i.

  5. 1−1i+1.

Definition 8.3.17.

Given a sequence {xn}1∞ and a sequence of the form {sn}1∞:={xn−xn+1}1∞ we call the series Sn=∑i=1nsi=∑i=1n(xi−xi+1) to be a telescoping series.

Activity 8.3.18.

Given a telescoping series Sn=∑i=1nsi=∑i=1n(xi−xi+1), find:

  1. S2.

  2. S10.

  3. Choose Sn from the following options:

    1. x1−xn

    2. x1−xn+1

    3. x1−xn−1

    4. x1−xn+1

    5. x1−xn−1

Activity 8.3.19.

For each of the following telescoping series, find the closed form for the nth partial sum.

  1. Sn=∑i=1n(2−i−(2−i−1)).

  2. Sn=∑i=1n(i2−(i+1)2).

  3. Sn=∑i=1n(12i+1−12i+3).

Activity 8.3.20.

Given the closed forms you found in Activity 8.3.19, determine which of the following telescoping series converge. If so, to what value does it converge?

  1. ∑i=1∞(2−i−(2−i−1)).

  2. ∑i=1∞(i2−(i+1)2).

  3. ∑i=1∞(12i+1−12i+3).

Activity 8.3.21.

Consider the partial sum sequence An=(−2)+(23)+(−29)+⋯+(−2⋅(−13)n).

Subsection 8.3.1 Videos

Figure 151. Video: Compute the first few terms of a telescoping or geometric partial sum sequence, and find a closed form for this sequence, and compute its limit.