Section 5.8 Improper integrals (TI8)
Learning Outcomes
I can compute improper integrals.
Activity 5.8.1.
Consider \(\displaystyle f(x)=\frac{1}{x^2}\text{.}\) Compute the following definite integrals.
(a)
\(\displaystyle \int_{0.1}^1 \frac{1}{x^2} dx\)
(b)
\(\displaystyle \int_{0.01}^1 \frac{1}{x^2} dx\)
(c)
\(\displaystyle \int_{0.001}^1 \frac{1}{x^2} dx\)
Activity 5.8.2.
(a)
What do you notice about \(\displaystyle \int_{a}^1 \frac{1}{x^2} dx\) as \(a\) approached 0 in Activity 5.8.1?
\(\displaystyle \int_{a}^1 \frac{1}{x^2} dx\) approaches a finite, non-zero constant.
\(\displaystyle \int_{a}^1 \frac{1}{x^2} dx\) approaches \(0\text{.}\)
\(\displaystyle \int_{a}^1 \frac{1}{x^2} dx\) approaches \(\infty\text{.}\)
\(\displaystyle \int_{a}^1 \frac{1}{x^2} dx\) approaches \(-\infty\text{.}\)
There is not enough information.
(b)
Why can't \(a=0\text{?}\)
Activity 5.8.3.
We still are considering \(f(x)=\frac{1}{x^2}\text{.}\) Compute the following definite integrals.
(a)
\(\displaystyle \int_{1}^{10} \frac{1}{x^2} dx\)
(b)
\(\displaystyle \int_{1}^{100} \frac{1}{x^2} dx\)
(c)
\(\displaystyle \int_{1}^{1000} \frac{1}{x^2} dx\)
Activity 5.8.4.
What do you notice about \(\displaystyle \int_{1}^a \frac{1}{x^2} dx\) as \(a\) approached \(\infty\) in Activity 5.8.3?
\(\displaystyle \int_{1}^a \frac{1}{x^2} dx\) approaches a finite, non-zero constant.
\(\displaystyle \int_{1}^a \frac{1}{x^2} dx\) approaches \(0\text{.}\)
\(\displaystyle \int_{1}^a \frac{1}{x^2} dx\) approaches \(\infty\text{.}\)
\(\displaystyle \int_{1}^a \frac{1}{x^2} dx\) approaches \(-\infty\text{.}\)
There is not enough information.
Activity 5.8.5.
Compute the following definite integrals.
(a)
\(\displaystyle \int_{0.1}^1 \frac{1}{\sqrt{x}} dx\)
(b)
\(\displaystyle \int_{0.01}^1 \frac{1}{\sqrt{x}} dx\)
(c)
\(\displaystyle \int_{0.001}^1 \frac{1}{\sqrt{x}} dx\)
Activity 5.8.6.
(a)
What do you notice about the integral \(\displaystyle \int_{a}^1 \frac{1}{\sqrt{x}} dx\) as \(a\) approached 0 in Activity 5.8.5?
\(\displaystyle \int_{a}^1 \frac{1}{\sqrt{x}} dx\) approaches a finite, non-zero constant.
\(\displaystyle \int_{a}^1 \frac{1}{\sqrt{x}} dx\) approaches \(0\text{.}\)
\(\displaystyle \int_{a}^1 \frac{1}{\sqrt{x}} dx\) approaches \(\infty\text{.}\)
\(\displaystyle \int_{a}^1 \frac{1}{\sqrt{x}} dx\) approaches \(-\infty\text{.}\)
There is not enough information.
(b)
How does this compare to what you found in Activity 5.8.1?
Activity 5.8.7.
Compute the following definite integrals.
(a)
\(\displaystyle \int_{1}^{10} \frac{1}{\sqrt{x}} dx\)
(b)
\(\displaystyle \int_{1}^{100} \frac{1}{\sqrt{x}} dx\)
(c)
\(\displaystyle \int_{1}^{1000} \frac{1}{\sqrt{x}} dx\)
Activity 5.8.8.
(a)
What do you notice the integral \(\displaystyle \int_{1}^a \frac{1}{\sqrt{x}} dx\) as \(a\) approached \(\infty\) in Activity 5.8.7?
\(\displaystyle \int_{1}^a \frac{1}{\sqrt{x}} dx\) approaches a finite, non-zero constant.
\(\displaystyle \int_{1}^a \frac{1}{\sqrt{x}} dx\) approaches \(0\text{.}\)
\(\displaystyle \int_{1}^a \frac{1}{\sqrt{x}} dx\) approaches \(\infty\text{.}\)
\(\displaystyle \int_{1}^a \frac{1}{\sqrt{x}} dx\) approaches \(-\infty\text{.}\)
There is not enough information.
(b)
How does this compare to what you found in Activity 5.8.3?
Definition 5.8.9.
For a function \(f(x)\) and a constant \(c\text{,}\) we let \(\displaystyle \int_c^\infty f(x) dx\) denote
If this limit is a defined real number, then we say \(\displaystyle \int_c^\infty f(x) dx\) is convergent. Otherwise, it is divergent.
Similarly,
Activity 5.8.10.
Which of the following is \(\displaystyle \int_1^a \frac{1}{x^2} dx\text{?}\)
\(\displaystyle -\frac{1}{x}+C\)
\(\displaystyle -\frac{1}{a}+C\)
\(\displaystyle -\frac{1}{x}+1\)
\(\displaystyle -\frac{1}{a}\)
\(\displaystyle -\frac{1}{a}+1\)
Activity 5.8.11.
Using your choice in Activity 5.8.10, what is \(\lim_{a\to \infty} \int_1^a \frac{1}{x^2} dx\text{?}\)
\(\displaystyle 0\)
\(\displaystyle 1\)
\(\displaystyle 2\)
\(\displaystyle \infty\)
\(\displaystyle -\infty\)
Activity 5.8.12.
(a)
Find \(\displaystyle \int_{\pi/2}^a \cos(x)dx\text{.}\)
(b)
Which of the following is true about \(\int_{\pi/2}^\infty \cos(x)dx\text{?}\)
\(\displaystyle \int_{\pi/2}^\infty \cos(x)dx\) is convergent.
\(\displaystyle \int_{\pi/2}^\infty \cos(x)dx\) is divergent.
More information is needed.
Definition 5.8.13.
For a function \(f(x)\) with a vertical asymptote at \(x=b\) and a constant \(c\text{,}\) we let \(\displaystyle \int_c^b f(x) dx\) denote
Similarly,
Activity 5.8.14.
(a)
Find \(\displaystyle \int_{a}^1 \frac{1}{\sqrt{x}} dx\text{.}\)
(b)
Using the above result and an appropriate limit, find \(\displaystyle \int_{0}^1 \frac{1}{\sqrt{x}} dx\text{.}\)
Activity 5.8.15.
(a)
Find \(\displaystyle \int_{a}^1 \frac{1}{x^2} dx\text{.}\)
(b)
Using the above result and an appropriate limit, find \(\displaystyle \int_{0}^1 \frac{1}{x^2} dx\text{.}\)
Fact 5.8.16.
Suppose that \(0< p\) and \(p\neq 1\text{.}\) Applying the integration power rule gives us the indefinite integral \(\displaystyle \int \frac{1}{x^p} dx=\frac{1}{(1-p)}x^{1-p}+C\text{.}\)
Activity 5.8.17.
(a)
If \(0< p< 1\text{,}\) which of the following statements must be true? Select all that apply.
\(\displaystyle 1-p< 0\)
\(\displaystyle 1-p> 0\)
\(\displaystyle 1-p< 1\)
\(\displaystyle \int_1^\infty \frac{1}{x^p} dx\) converges.
\(\displaystyle \int_1^\infty \frac{1}{x^p} dx\) diverges.
(b)
If \(p>1\text{,}\) which of the following statements must be true? Select all that apply.
\(\displaystyle 1-p< 0\)
\(\displaystyle 1-p> 0\)
\(\displaystyle 1-p< 1\)
\(\displaystyle \int_1^\infty \frac{1}{x^p} dx\) converges.
\(\displaystyle \int_1^\infty \frac{1}{x^p} dx\) diverges.
Activity 5.8.18.
(a)
If \(0< p< 1\text{,}\) which of the following statements must be true?
\(\displaystyle \int_0^1 \frac{1}{x^p} dx\) converges.
\(\displaystyle \int_0^1 \frac{1}{x^p} dx\) diverges.
(b)
If \(p>1\text{,}\) which of the following statements must be true?
\(\displaystyle \int_0^1 \frac{1}{x^p} dx\) converges.
\(\displaystyle \int_0^1 \frac{1}{x^p} dx\) diverges.
Activity 5.8.19.
Consider when \(p=1\text{.}\) Then \(\frac{1}{x^p}=\frac{1}{x}\) and \(\displaystyle \int \frac{1}{x^p}\ dx=\displaystyle \int \frac{1}{x}\ dx=\ln|x|+C\text{.}\)
(a)
What can we conclude about \(\displaystyle \int_1^\infty \frac{1}{x} dx\text{?}\)
\(\displaystyle \int_1^\infty \frac{1}{x} dx\) converges.
\(\displaystyle \int_1^\infty \frac{1}{x} dx\) diverges.
There is not enough information to determine whether this integral converges or diverges.
(b)
What can we conclude about \(\displaystyle \int_0^1 \frac{1}{x} dx\text{?}\)
\(\displaystyle \int_0^1 \frac{1}{x} dx\) converges.
\(\displaystyle \int_0^1 \frac{1}{x} dx\) diverges.
There is not enough information to determine whether this integral converges or diverges.
Fact 5.8.20.
Let \(c, p>0\text{.}\)
\(\displaystyle \int_0^c \frac{1}{x^p} dx\) is defined if and only if \(p< 1\text{.}\)
\(\displaystyle \int_c^\infty \frac{1}{x^p} dx\) is defined if and only if \(p> 1\text{.}\)
Activity 5.8.21.
Consider the plots of \(f(x), g(x), h(x) \) where \(0 < g(x) < f(x) < h(x)\text{.}\)
If \(\displaystyle \int_1^\infty f(x) dx\) is convergent, what can we say about \(g(x), h(x)\text{?}\)
\(\displaystyle \int_1^\infty g(x) dx\) and \(\displaystyle \int_1^\infty h(x) dx\) are both convergent.
\(\displaystyle \int_1^\infty g(x) dx\) and \(\displaystyle \int_1^\infty h(x) dx\) are both divergent.
Whether or not \(\displaystyle \int_1^\infty g(x) dx\) and \(\displaystyle \int_1^\infty h(x) dx\) are convergent or divergent cannot be determined.
\(\displaystyle \int_1^\infty g(x) dx\) is convergent and \(\displaystyle \int_1^\infty h(x) dx\) is divergent.
\(\displaystyle \int_1^\infty g(x) dx\) is convergent and \(\displaystyle \int_1^\infty h(x) dx\) could be either convergent or divergent.
Activity 5.8.22.
Consider the plots of \(f(x), g(x), h(x) \) where \(0 < g(x) < f(x) < h(x)\text{.}\) If \(\displaystyle \int_1^\infty f(x) dx\) is divergent, what can we say about \(g(x), h(x)\text{?}\)
\(\displaystyle \int_1^\infty g(x) dx\) and \(\displaystyle \int_1^\infty h(x) dx\) are both convergent.
\(\displaystyle \int_1^\infty g(x) dx\) and \(\displaystyle \int_1^\infty h(x) dx\) are both divergent.
Whether or not \(\displaystyle \int_1^\infty g(x) dx\) and \(\displaystyle \int_1^\infty h(x) dx\) are convergent or divergent cannot be determined.
\(\displaystyle \int_1^\infty g(x) dx\) could be either convergent or dicergent and \(\displaystyle \int_1^\infty h(x) dx\) is divergent.
\(\displaystyle \int_1^\infty g(x) dx\) is convergent and \(\displaystyle \int_1^\infty h(x) dx\) is divergent.
Activity 5.8.23.
Consider the plots of \(f(x), g(x), h(x) \) where \(0 < g(x) < f(x) < h(x)\text{.}\) If \(\displaystyle \int_0^1 f(x) dx\) is convergent, what can we say about \(g(x)\) and \(h(x)\text{?}\)
\(\displaystyle \int_0^1 g(x) dx\) and \(\displaystyle \int_0^1 h(x) dx\) are both convergent.
\(\displaystyle \int_0^1 g(x) dx\) and \(\displaystyle \int_0^1 h(x) dx\) are both divergent.
Whether or not \(\displaystyle \int_0^1 g(x) dx\) and \(\displaystyle \int_0^1 h(x) dx\) are convergent or divergent cannot be determined.
\(\displaystyle \int_0^1 g(x) dx\) is convergent and \(\displaystyle \int_0^1 h(x) dx\) is divergent.
\(\displaystyle \int_0^1 g(x) dx\) is convergent and \(\displaystyle \int_0^1 h(x) dx\) can either be convergent or divergent.
Activity 5.8.24.
Consider the plots of \(f(x), g(x), h(x) \) where \(0 < g(x) < f(x) < h(x)\text{.}\) If \(\displaystyle \int_0^1 f(x) dx\) is dinvergent, what can we say about \(g(x)\) and \(h(x)\text{?}\)
\(\displaystyle \int_0^1 g(x) dx\) and \(\displaystyle \int_0^1 h(x) dx\) are both convergent.
\(\displaystyle \int_0^1 g(x) dx\) and \(\displaystyle \int_0^1 h(x) dx\) are both divergent.
Whether or not \(\displaystyle \int_0^1 g(x) dx\) and \(\displaystyle \int_0^1 h(x) dx\) are convergent or divergent cannot be determined.
\(\displaystyle \int_0^1 g(x) dx\) can be either convergent or divergent and \(\displaystyle \int_0^1 h(x) dx\) is divergent.
\(\displaystyle \int_0^1 g(x) dx\) is convergent and \(\displaystyle \int_0^1 h(x) dx\) is divergent.
Fact 5.8.25.
Let \(f(x), g(x), h(x)\) be functions such that over a region \(I\text{,}\) \(g(x) < f(x) < h(x)\text{.}\) Then for the integrals \(\displaystyle \int_I f(x) dx, \int_I g(x) dx, \int_I h(x) dx\text{:}\)
If \(f(x)\) converges, so does \(g(x)\text{.}\) We need more information to conclude anything about \(h(x)\text{.}\)
If \(f(x)\) diverges, so does \(h(x)\text{.}\) We need more information to conclude anything about \(g(x)\text{.}\)
Activity 5.8.26.
Compare \(\frac{1}{x^3+1}\) to one of the following functions where \(x>2\) and use this to determine if \(\displaystyle \int_2^\infty \frac{1}{x^3+1}dx\) is convergent or divergent.
\(\displaystyle \displaystyle\frac{1}{x}\)
\(\displaystyle \displaystyle\frac{1}{\sqrt{x}}\)
\(\displaystyle \displaystyle\frac{1}{x^2}\)
\(\displaystyle \displaystyle\frac{1}{x^3}\)